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Submission
# When Author Problem Language CPU Memory
3655 2021-12-25 18:25:04 ewu_ieee21_user_34 Find MinMaxXoR Number C++ 11 1115 ms 39560 kb Time Limit Exceeded - 10
Test Cases
# CPU Memory Points
1 16 ms 19064 kb 1 Accepted
2 13 ms 19024 kb 1 Accepted
3 16 ms 19084 kb 1 Accepted
4 18 ms 19820 kb 1 Accepted
5 17 ms 22812 kb 1 Accepted
6 19 ms 25496 kb 1 Accepted
7 46 ms 35084 kb 1 Accepted
8 52 ms 35192 kb 1 Accepted
9 287 ms 39560 kb 1 Accepted
10 1115 ms 660 kb 0 Time Limit Exceeded
11 0 ms 0 kb 0 Skipped
12 0 ms 0 kb 0 Skipped
13 0 ms 0 kb 0 Skipped
14 0 ms 0 kb 0 Skipped
15 0 ms 0 kb 0 Skipped
16 0 ms 0 kb 0 Skipped
Source Code
  1. #include<bits/stdc++.h>
  2. #include<ext/pb_ds/assoc_container.hpp>
  3. #include<ext/pb_ds/tree_policy.hpp>
  4. using namespace std;
  5. using namespace __gnu_pbds;
  6.  
  7. template <typename num_t>
  8. using ordered_set = tree<num_t,null_type,less<num_t>,rb_tree_tag,tree_order_statistics_node_update>;
  9.  
  10. const int DEBUGGER = 0;
  11.  
  12. #define io ios_base::sync_with_stdio(0); cin.tie(NULL)
  13. #define mset(a,v) memset(a,v,sizeof(a))
  14. #define lp(i,a,n) for(int i=a;i<n;i++)
  15. #define lpr(i,a,n) for(int i=n-1;i>=a;i--)
  16. #define stlp(it,stl) for(__typeof(stl.begin()) it=stl.begin();it!=stl.end();it++)
  17. #define stlpr(it,stl) for(__typeof(stl.rbegin()) it=stl.rbegin();it!=stl.rend();it++)
  18. #define r(a) a.begin(),a.end()
  19. #define II ({ ll TEMP; cin>>TEMP; TEMP; })
  20. #define SI ({ string TEMP; cin>>TEMP; TEMP; })
  21. #define AI(a) ({ int n=sizeof(a)/sizeof(a[0]); lp(I,0,n)a[I]=II; })
  22. #define AO(a) ({ int n=sizeof(a)/sizeof(a[0]); lp(I,0,n){cout<<(I?" ":"")<<a[I];} if(DEBUGGER)cout<<endl;else cout<<'\n'; })
  23. #define VI(v) ({ lp(I,0,v.size())v[I]=II; })
  24. #define VO(v) ({ lp(I,0,v.size()){cout<<(I?" ":"")<<v[I];} if(DEBUGGER)cout<<endl;else cout<<'\n'; })
  25. #define outa(a) ({ if(DEBUGGER)dbg(a); else cout<<a<<'\n'; })
  26. #define dbg(a) ({ if(DEBUGGER)cout<<#a<<" = "<<a<<endl; })
  27. #define cbit(n,p) ((n)&(1LL<<(p)))
  28. #define sbit(n,p) ((n)|(1LL<<(p)))
  29. #define tbit(n,p) ((n)^(1LL<<(p)))
  30. #define F first
  31. #define S second
  32.  
  33. typedef long long ll;
  34. typedef pair<ll,ll> pll;
  35. typedef vector<ll> vl;
  36.  
  37. const ll MAX = 5e5+5;
  38. const ll MOD = 1e9+7;
  39. const ll INF = 9e18;
  40. const double PI = 3.141592653589793238462;
  41. ll addM(ll a,ll b){return (a+=b)>=MOD?(a-=MOD):a;}
  42. ll subM(ll a,ll b){return (a-=b)<0?(a+=MOD):a;}
  43.  
  44. ll n,a[MAX],mxvis[2][2][(ll)1e6+6];
  45. pll trN[4*MAX];
  46.  
  47. void combine(pll &trP,pll &trL,pll &trR){
  48. trP={max(trL.F,trR.F),min(trL.S,trR.S)};
  49. }
  50.  
  51. void init(int n,int l,int r){
  52. if(l==r) return void(trN[n]={a[l],a[l]});
  53. int m=(l+r)/2;
  54. init(2*n,l,m);
  55. init(2*n+1,m+1,r);
  56. combine(trN[n],trN[2*n],trN[2*n+1]);
  57. }
  58.  
  59. ll query(int n,int l,int r,int i,int j,int c,int d,ll val,ll ix){
  60. if(j<i) return 0;
  61. if(j<l || r<i) return -1;
  62. if(i<=l && r<=j){
  63. if(trN[n].S>=val && c==0 && d==0 && mxvis[c][d][val]>ix)return r-l+1;
  64. if(trN[n].S>val && c==0 && d==0 && mxvis[c][d][val]<ix)return r-l+1;
  65. if(trN[n].S>=val && c==0 && d==1 && mxvis[c][d][val]<ix)return r-l+1;
  66. if(trN[n].S>val && c==0 && d==1 && mxvis[c][d][val]>ix)return r-l+1;
  67.  
  68. if(trN[n].F<=val && c==1 && d==0 && mxvis[c][d][val]>ix)return r-l+1;
  69. if(trN[n].F<val && c==1 && d==0 && mxvis[c][d][val]<ix)return r-l+1;
  70. if(trN[n].F<=val && c==1 && d==1 && mxvis[c][d][val]<ix)return r-l+1;
  71. if(trN[n].F<val && c==1 && d==1 && mxvis[c][d][val]>ix)return r-l+1;
  72.  
  73. // if(trN[n].F<=val && c==1 && d==0 && mxvis[c][d][val]<a[i])return r-l+1;
  74. // if(trN[n].F<val && c==1 && d==0 && mxvis[c][d][val]>a[i])return r-l+1;
  75. // if(trN[n].F<=val && c==1 && d==1 && mxvis[c][d][val]<ix)return r-l+1;
  76. // if(trN[n].F<val && c==1 && d==1 && mxvis[c][d][val]>a[i])return r-l+1;
  77. if(l==r) return 0;
  78. }
  79. int m=(l+r)/2;
  80. ll trQL=0,trQR=0;
  81. if(d==0){
  82. trQR=query(2*n+1,m+1,r,i,j,c,d,val,ix);
  83. if(trQR==min(r,j)-max(m+1,i)+1 || trQR==-1)
  84. trQL=query(2*n,l,m,i,j,c,d,val,ix);
  85. }
  86. else{
  87. trQL=query(2*n,l,m,i,j,c,d,val,ix);
  88. if(trQL==min(m,j)-max(l,i)+1 || trQL==-1)
  89. trQR=query(2*n+1,m+1,r,i,j,c,d,val,ix);
  90. }
  91. trQL=max(trQL,0LL);
  92. trQR=max(trQR,0LL);
  93. return trQL+trQR;
  94. }
  95.  
  96. void solve(){
  97. lp(i,0,MAX)
  98. mxvis[0][0][i]=INF,
  99. mxvis[1][0][i]=INF,
  100. mxvis[0][1][i]=-1,
  101. mxvis[1][1][i]=-1;
  102. n=II;
  103. lp(i,1,n+1)a[i]=II;
  104. init(1,1,n);
  105. ll ans=0;
  106. lp(i,1,n+1){
  107. ll minleftsz=query(1,1,n,1,i-1,0,0,a[i],i);
  108. ll minrightsz=query(1,1,n,i+1,n,0,1,a[i],i);
  109.  
  110. ll maxleftsz=query(1,1,n,1,i-1,1,0,a[i],i);
  111. ll maxrightsz=query(1,1,n,i+1,n,1,1,a[i],i);
  112.  
  113. // mxvis[0][1][a[i]]=i+minrightsz;
  114. // mxvis[0][0][a[i]]=i-minleftsz;
  115. //
  116. // mxvis[1][1][a[i]]=i+maxrightsz;
  117. // mxvis[1][0][a[i]]=i-maxleftsz;
  118.  
  119. mxvis[0][1][a[i]]=i;
  120. mxvis[0][0][a[i]]=i;
  121.  
  122. mxvis[1][1][a[i]]=i;
  123. mxvis[1][0][a[i]]=i;
  124.  
  125. ll minsubarrsz=(minleftsz+1)*(minrightsz+1)-1;
  126. if(minsubarrsz&1)ans^=a[i];
  127.  
  128. ll maxsubarrsz=(maxleftsz+1)*(maxrightsz+1)-1;
  129. if(maxsubarrsz&1)ans^=a[i];
  130.  
  131. dbg(minleftsz<<' '<<minrightsz<<' '<<maxleftsz<<' '<<maxrightsz<<' '<<a[i]);
  132. dbg(minsubarrsz<<' '<<maxsubarrsz);
  133. }
  134. outa(ans);
  135. }
  136.  
  137. int main(void){
  138. io;
  139. int multipletest=0;
  140. if(multipletest){
  141. int tc;
  142. cin>>tc;
  143. while(tc--)
  144. solve();
  145. }
  146. else
  147. solve();
  148. return 0;
  149. }
  150.